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linux: Set timeout argument on poll() properly
`0` for the timeout means *return immediately* instead of *wait forever*. This is absolutely unnecessary, so change the argument to `-1` which does mean *wait until something happens*.
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@ -540,7 +540,7 @@ int main(int argc, char **argv)
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fds[i].revents = 0;
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}
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if (poll(fds, 2, 0) < 0) {
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if (poll(fds, 2, -1) < 0) {
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perror("poll");
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exit(1);
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}
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@ -92,7 +92,7 @@ int main(int argc, char **argv) {
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fds[i].revents = 0;
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}
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if (poll(fds, 2, 0) < 0) {
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if (poll(fds, 2, -1) < 0) {
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fprintf(stderr, "Poll error: %s\n", strerror(errno));
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exit(1);
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}
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